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36=25+c^2-2*5c*0.5
We move all terms to the left:
36-(25+c^2-2*5c*0.5)=0
We get rid of parentheses
-c^2+2*5c*0.5-25+36=0
We add all the numbers together, and all the variables
-1c^2+2*5c*0.5+11=0
Wy multiply elements
-1c^2+5c+11=0
a = -1; b = 5; c = +11;
Δ = b2-4ac
Δ = 52-4·(-1)·11
Δ = 69
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{69}}{2*-1}=\frac{-5-\sqrt{69}}{-2} $$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{69}}{2*-1}=\frac{-5+\sqrt{69}}{-2} $
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